MATH SOLVE

4 months ago

Q:
# The center of a circle is at (−5, 2) and its radius is 7. What is the equation of the circle? (x−5)2+(y+2)2=14 (x+5)2+(y−2)2=49 (x+5)2+(y−2)2=14 (x−5)2+(y+2)2=49

Accepted Solution

A:

The standard equation of a circle is in the form:(x-a)^2 + (y-b)^2 = r^2where; a is the x coordinate of the center, b is the y coordinate of the center, and r is the radius of the center.In this case, a is -5, b is 2, and r is 7.Therefore, the equation of this circle would be(x+5)^2 + (y-2)^2 = 49