MATH SOLVE

4 months ago

Q:
# 42 was divided by some number, then added to 11 next this sum was multiplied by 5, which gave a product of 125. Find this number.

Accepted Solution

A:

Answer:The desired such number is 3.Step-by-step explanation:Let the given such number = mNow, 42 is divided by m ⇒[tex]\frac{42}{m}[/tex] is the desired expression.Now, The quotient is added to 11.⇒[tex]\frac{42}{m} + 11[/tex] is the desired expression.The sum is again multiplied by 5. ⇒[tex](\frac{42}{m} + 11) \times 5[/tex] is the desired expression.The product is 125.⇒[tex](\frac{42}{m} + 11) \times 5 = 125[/tex] is the desired expression.Now, solving for the value of m , we get:[tex](\frac{42}{m} + 11) \times 5 = 125 \implies(\frac{42}{m} + 11) = \frac{125}{5} \\or, (\frac{42}{m} + 11) = 25\\or, (\frac{42}{m} ) = 25 - 11 = 14[/tex]⇒[tex]\frac{42}{m} = 14 \implies m = \frac{42}{14} = 3[/tex]or, m = 3Hence, the desired such number is 3.