What is the factored form of 6n4 – 24n3 + 18n?

Answer:6n(n - 1)(n^2 - 3n - 3).Step-by-step explanation:The GCF  = 6n.6n^4 - 24n^3 + 18n= 6n(n^3 - 4n^2 + 3)Putting n = 1 in the expression in the parentheses:(1)^3 - 4(1)^2 + 3 = 0  so n - 1 is a factor.Dividing:n - 1 ) n^3 - 4n^2 + 0n  + 3 ( n^2 - 3n - 3          n^3 - n^2                    -3n^2 + 0n                    -3n62 + 3n                                - 3n + 3                                 -3n + 3  So the factors are 6n(n - 1)(n^2 - 3n - 3).