42 was divided by some number, then added to 11 next this sum was multiplied by 5, which gave a product of 125. Find this number.

Answer:The desired such number is 3.Step-by-step explanation:Let the given such number  = mNow, 42 is divided by m ⇒[tex]\frac{42}{m}[/tex]   is the desired expression.Now, The quotient is added to 11.⇒[tex]\frac{42}{m}  + 11[/tex]   is the desired expression.The sum is again multiplied by 5. ⇒[tex](\frac{42}{m} + 11) \times 5[/tex]   is the desired expression.The product is 125.⇒[tex](\frac{42}{m} + 11) \times 5   = 125[/tex]   is the desired expression.Now, solving for the value of m , we get:[tex](\frac{42}{m} + 11) \times 5   = 125  \implies(\frac{42}{m} + 11)   = \frac{125}{5} \\or, (\frac{42}{m} + 11)   = 25\\or, (\frac{42}{m} )  =  25 -  11 = 14[/tex]⇒[tex]\frac{42}{m}   = 14 \implies   m   =  \frac{42}{14}   = 3[/tex]or, m  = 3Hence, the desired such number is 3.